Max wattage 200amp panel

240*200=48,000watts. 80% is 38,400watts. 12 S19J 104’s are 36,816watts. Is that math correct?

Thanks

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I am not an electrician but I will shed some light on your question. Your math is correct but putting 12 S19J 104TH miners on a 240V 200A panel is something I would personally not do.

If you are going to plug each miner into its’ own circuit, you will need a 20A breaker (at a minimum) for each miner. If you have a 200A panel, you will only be able to put 10 separate 20A breaker circuits in that panel…10 miners X 20A breakers = 200A panel.

Again, I am not an electrician and this is just my opinion. Many people would choose to plug each miner into a 30A breaker which would result in even less miners on your 200A panel. Somebody else on this forum with more electric experience may be able to give better advice.

That sounds about right. Assuming this panel is dedicated to your mining rigs.
If this is the house panel and you have a mix of 120 and 240v appliances… it gets complicated very quickly.

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lol… does it… wonder if they wired half this room into that room… haha. had mine poping like popcorn till i figured out how they ran it randomly. 16,000+kw a month later on factory 120 breaker box from house

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If it’s a panel just for rigs, will 12 S19’s work on 4 240/50amp PDUs? Each pdu is good for 9600watts.

u could put that on 1 50amp

How do you put 36,800 watts on 1 50amp? Serious question because I don’t really understand most of this lol.

I’m a licensed electrician by trade

What exactly are you asking ?
What is your goal ?

Can I put 12 S19J 104’s on a 200amp panel? 12=36,816watts

Master Electrician here. Your math is correct. And I understand that will be the only loads on that panel? And it’s a single phase service? 120/240v

Adding up your breaker sizes does not dictate the total load of your panel. Load calculations are what we use. And the devices on your panel are all considered continuous duty (operating for 3 hours or more). So each branch circuit and the panelboard itself must be sized at 125%.

1- s19 (minimum circuit size)
3068w x 125% = 3835w.
3835/240v = 15.97amps

So you really can’t run two on a 30amp circuit with a PDU. (Limited to 24a)

I would run 20 amp 240 circuits. And find some c13 to nema 6-20r cables. Install 2 plugs per circuit as the s19 will require 2 c13 plugs.

I also installed a seperate 200a service for my setup. I’m using 30 amp circuits and small pdus. I have mostly L3 units so it worked out well with the 30a circuits.

I work as an electrician in a data center and put over 80 megawatts to use everyday testing massive supercomputer systems before they ship out to customers. I helped design all of our electrical infrastructure. So I can help if anyone wants to go large scale

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thanks for the clarification and the great explanation

awesome. looking forward to your expertise.

Using real life figures.
17amps/unit=16x230(real life voltage)=3680w
3680x12= 44160
For arguments sake
you install is 240*200=48000
80% 38400
AND
Power correction factor of 80%
Gives 30,720w or 8-9(MAX) units
my 0.02USDT

Steve,

Your not wrong on using the power factor to determine apparent power. However most of the equipment I deal with and bitmain have a very high power factor. Almost perfect. So there is little to no loss.

Bitmains info on apw12 psu shows .99 PF
https://m.bitmain.com/product/detail?pid=00020210304155450857gzkpJ1Ah06D4

Total available kw
200a240v80%= 38400w
38400/1000 = 38.4kw

Apparant power (kVa) per unit
S19 104t
kVa=kw/PF
KVa= (3.068/.99)
kVa= 3.098

Total s19 104th
38.4kw/3.098kva = 12.39 units

To OP, if you are selecting a panel for this project I would recommend square D QO series. Every panel mfg seems to have cheaper residential versions available, and when running cont. duty loads I would not be using them.

Here is a illustration I like to use.

"The combination of drinkable beer (kW) and foam (kVAR) in your beer glass represents the Apparent Power, or KVA.

Power Factor is simply the ratio of Real Power (kW) to Apparent Power (kVA) and is represented by this formula: PF = KW / KVA."

Looks like (4) 50a PDU’s would also work for you.
9600w/3,098kva= 3.09 units per PDU.

If you get fancy PDU they will have the amperage displayed on them which is nice.

It all depends on what you want to spend and what the future needs may be.

I would think your cheapest installation would be the individual circuits.

Apw12 power factor is .99

Any motor that ramps up with variable speed and amperage- power factor of 0.85. The asic has the power factor, not the power supply- fans, capacitors, processing chips have variable loads, it’s not 5% +or minus 15amps.
This is what causes damaged equipment.

I would recommend 6-20 to c13 y power splitters, connected to a 6-20 outlet with 10-2 or 12-2 AWG wire rated for 250v from a double pole 30amp breaker coming from your box. You need to use the c13 splitter.

Asic Miner Panels has a Sub panel with 4 240/50 PDU’s for $1,195. Each one has 6xC13 cables. This is probably what I’m going with. Growing bigger in the future will require a service upgrade.

@Colby_DuPont where would you find these splitters? I can definetly find a 6-20p to c13 splitter but they all have 14/3 wire, not 10/2 or 12/2. For example, here a listing where the cord is 14/3 https://www.pduwhips.com/products/2127-6-20p-to-c13-y-splitter-power-cables.aspx

@Kosakoskim I’ve got some questions. I’m working with a couple of other guys to set up a small to start, but hopefully medium/large sized farm. We are starting by renting a garage that isn’t being used. I don’t know what amperage service it has at the moment, but we will likely be needing to upgrade it to 200 Amp service, but now we are wondering if it is worth just going to 400 amp service. We are going to be running all the electrical for the miners from scratch, and we are looking at starting with about 6 L7s and then moving up to 12+. What are your recommendations, considering we will need to keep the owner’s garage doors functional, a minimal number of lights, and then we will be adding some substantial ventilation fans (about 8000CFM)??? Then I’ve got bigger questions for when we move to a large facility, but those can come later.